Optimal. Leaf size=100 \[ b \text {Int}\left (\frac {\tan ^{-1}(c x) \left (d+e x^2\right )^{5/2}}{x},x\right )-a d^{5/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d}}\right )+a d^2 \sqrt {d+e x^2}+\frac {1}{3} a d \left (d+e x^2\right )^{3/2}+\frac {1}{5} a \left (d+e x^2\right )^{5/2} \]
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Rubi [A] time = 0.20, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x} \, dx &=a \int \frac {\left (d+e x^2\right )^{5/2}}{x} \, dx+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx\\ &=\frac {1}{2} a \operatorname {Subst}\left (\int \frac {(d+e x)^{5/2}}{x} \, dx,x,x^2\right )+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx\\ &=\frac {1}{5} a \left (d+e x^2\right )^{5/2}+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx+\frac {1}{2} (a d) \operatorname {Subst}\left (\int \frac {(d+e x)^{3/2}}{x} \, dx,x,x^2\right )\\ &=\frac {1}{3} a d \left (d+e x^2\right )^{3/2}+\frac {1}{5} a \left (d+e x^2\right )^{5/2}+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx+\frac {1}{2} \left (a d^2\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d+e x}}{x} \, dx,x,x^2\right )\\ &=a d^2 \sqrt {d+e x^2}+\frac {1}{3} a d \left (d+e x^2\right )^{3/2}+\frac {1}{5} a \left (d+e x^2\right )^{5/2}+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx+\frac {1}{2} \left (a d^3\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {d+e x}} \, dx,x,x^2\right )\\ &=a d^2 \sqrt {d+e x^2}+\frac {1}{3} a d \left (d+e x^2\right )^{3/2}+\frac {1}{5} a \left (d+e x^2\right )^{5/2}+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx+\frac {\left (a d^3\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {d}{e}+\frac {x^2}{e}} \, dx,x,\sqrt {d+e x^2}\right )}{e}\\ &=a d^2 \sqrt {d+e x^2}+\frac {1}{3} a d \left (d+e x^2\right )^{3/2}+\frac {1}{5} a \left (d+e x^2\right )^{5/2}-a d^{5/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d}}\right )+b \int \frac {\left (d+e x^2\right )^{5/2} \tan ^{-1}(c x)}{x} \, dx\\ \end {align*}
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Mathematica [A] time = 83.07, size = 0, normalized size = 0.00 \[ \int \frac {\left (d+e x^2\right )^{5/2} \left (a+b \tan ^{-1}(c x)\right )}{x} \, dx \]
Verification is Not applicable to the result.
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fricas [A] time = 0.44, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (a e^{2} x^{4} + 2 \, a d e x^{2} + a d^{2} + {\left (b e^{2} x^{4} + 2 \, b d e x^{2} + b d^{2}\right )} \arctan \left (c x\right )\right )} \sqrt {e x^{2} + d}}{x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.11, size = 0, normalized size = 0.00 \[ \int \frac {\left (e \,x^{2}+d \right )^{\frac {5}{2}} \left (a +b \arctan \left (c x \right )\right )}{x}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [A] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\left (a+b\,\mathrm {atan}\left (c\,x\right )\right )\,{\left (e\,x^2+d\right )}^{5/2}}{x} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {atan}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{\frac {5}{2}}}{x}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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